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Physics Asked by a SnapAndSolve user · about 2 hours ago

An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If...

An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If air resistance is negligible, the time that it takes the object to fall to the ground from the cliff is most nearly
Select {responseValue}
25 s
Select {responseValue}
6 s
Select {responseValue}
5 s
Select {responseValue}
12 s
Select {responseValue}
3 s

Answer

To determine the time it takes for the object to fall to the ground, we can use the kinematic equation for vertical motion under constant acceleration due to gravity.
The relevant equation is:
\[
d = \frac{1}{2} g t^2
\]
where:
- \( d \) is the distance fallen (125 m),
- \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)),
- \( t \) is the time in seconds.
We need to solve for \( t \). Rearranging the equation gives:
\[
t^2 = \frac{2d}{g}
\]
Substituting in the known values:
\[
t^2 = \frac{2 \times 125 \, \text{m}}{9.81 \, \text{m/s}^2}
\]
\[
t^2 = \frac{250}{9.81} \approx 25.45
\]
Taking the square root of both sides:
\[
t \approx \sqrt{25.45} \approx 5.04 \, \text{s}
\]
Thus, the time the object takes to fall to the ground is approximately 5 seconds.
Therefore, the answer is:
5 s

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