A block of mass 2 kg is initially at rest on a horizontal surface. A horizontal force with a constant...
What is the magnitude of the frictional force exerted on the block by the surface?
To determine the magnitude of the frictional force exerted on the block by the surface, we start with the following information:
The maximum static friction force (F_friction_max) can be calculated using the formula:
F_friction_max = μ_s × N
Where N is the normal force. For an object resting on a horizontal surface without any vertical forces acting on it other than its weight, the normal force (N) is equal to the weight of the block:
N = m × g
Assuming acceleration due to gravity (g) is approximately 9.81 m/s², we calculate N:
N = 2 kg × 9.81 m/s² = 19.62 N
Now, we substitute the value of N into the static friction formula:
F_friction_max = 0.5 × 19.62 N = 9.81 N
The block is initially at rest, and the applied force of 8 N does not exceed the maximum static friction force of 9.81 N. Hence, the static frictional force will match the applied force to keep the block in equilibrium.
Therefore, the actual frictional force (F_friction) is equal to the applied force:
F_friction = F_applied = 8 N
The magnitude of the frictional force exerted on the block by the surface is:
F_friction = 8 N
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