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A 50.0 N box is at rest on a horizontal surface. The coefficient of static friction between the box and the...

4. A 50.0 N box is at rest on a horizontal surface. The coefficient of static friction between the box and the surface is 0.50, and the coefficient of kinetic friction is 0.30. A horizontal 20.0 N force is then exerted on the box. The magnitude of the acceleration of the box is most nearly

Answer

First, calculate the maximum static friction force: f_s = μ_s * N = 0.50 * 50.0 N = 25.0 N.

Since the applied force (20.0 N) is less than the maximum static friction force (25.0 N), the box does not move, and the acceleration is 0 m/s².

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