What sex is MOST likely to be carriers of colorblindness?
Why does individual IV-7 (a female) have colorblindness?
Can a carrier women have an affected son if married to a normal male? Explain.
The sex most likely to be carriers of colorblindness is females. Colorblindness is commonly an X-linked recessive trait, meaning it is located on the X chromosome. Males have one X and one Y chromosome (XY), so if they inherit an X chromosome with the colorblindness allele, they will express the trait since they do not have another X chromosome to counteract it. Females have two X chromosomes (XX), so they can be carriers if they inherit one X chromosome with the colorblindness allele without expressing the trait, provided their other X chromosome carries the normal allele.
Individual IV-7 likely has colorblindness because she has inherited two X chromosomes, both carrying the allele for colorblindness. Since colorblindness is an X-linked recessive trait, a female must have both copies of the allele (one from each parent) to express the trait. If her father has colorblindness, he contributes an X chromosome with the colorblindness allele. If her mother is either a carrier (XcX) or affected (XcXc), she would also pass on an X chromosome with the colorblindness allele. Hence, IV-7 has inherited the affected X chromosome from both parents and expresses colorblindness.
Yes, a carrier woman can have an affected son if she is married to a normal male. In this scenario, the carrier woman has one affected X chromosome (Xc) and one normal X chromosome (X). The normal male possesses one normal X chromosome (X) and one Y chromosome (Y). When they have a son, the son will inherit his X chromosome from his mother and a Y chromosome from his father. There are two possibilities:
Thus, there is a 50% chance that the son will be affected by colorblindness, depending on which X chromosome he inherits from his carrier mother.
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