The position of a particle moving along a straight horizontal groove is given by $x = 5 + t(t - 1)$ for...

Question

1. The position of a particle moving along a straight horizontal groove is given by $x = 5 + t(t - 1)$ for $0 \leq t \leq 5$ where $x(t)$ is measured in metres and $t$ in seconds.
What is the position of the particle at the following times:
At t = 0s the height of the ball will be: ______ metre
At t = 1s the height of the ball will be: ______ metre
At t = 1.5s the height of the ball will be: ______ metre
At t = 2s the height of the ball will be: ______ metre
At t = 3s the height of the ball will be: ______ metre
At t = 3.5s the height of the ball will be: ______ metre

SnapAndSolve AI · Accepted Answer

At t = 0s, x = 5 + 0(0 - 1) = 5 metres.
At t = 1s, x = 5 + 1(1 - 1) = 5 metres.
At t = 1.5s, x = 5 + 1.5(1.5 - 1) = 5 + 1.5(0.5) = 5.75 metres.
At t = 2s, x = 5 + 2(2 - 1) = 5 + 2 = 7 metres.
At t = 3s, x = 5 + 3(3 - 1) = 5 + 6 = 11 metres.
At t = 3.5s, x = 5 + 3.5(3.5 - 1) = 5 + 3.5(2.5) = 13.75 metres.

contact us

Contact Info

The position of a particle moving along a straight horizontal groove is given by \(x = 5 + t(t - 1)\) for...

Answer

Have a similar question?

More math questions