Solve the rational equation: \( \frac{x}{x+1} \cdot \frac{x+8}{2x} = \frac{5}{x+1} \) a. \( x = 2 \) b. \(...
a. \( x = 2 \)
b. \( x = 0 \)
c. \( x = -1 \)
d. No solution
First, simplify the equation:
\( \frac{x}{x+1} \cdot \frac{x+8}{2x} = \frac{5}{x+1} \)
Multiply both sides by \( x+1 \) to eliminate the denominator:
\( x \cdot \frac{x+8}{2x} = 5 \)
Cancel \( x \) in the numerator and denominator:
\( \frac{x+8}{2} = 5 \)
Multiply both sides by 2:
\( x+8 = 10 \)
Subtract 8 from both sides:
\( x = 2 \)
The solution is a. \( x = 2 \)
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