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Given the function: f(x) = \frac{x+7}{(x-3)(x+2)} Identify the vertical asymptotes. A. x = -7, 2 B. x = -7...

8. Given the function: f(x) = \frac{x+7}{(x-3)(x+2)} Identify the vertical asymptotes. A. x = -7, 2 B. x = -7 C. x = 3, -2 D. x = 7

Answer

The vertical asymptotes occur where the denominator is zero and the numerator is not zero.

  1. The denominator is (x-3)(x+2). Set each factor equal to zero: x-3=0 or x+2=0.
  2. Solving these gives x=3 and x=-2.
  3. Therefore, the vertical asymptotes are at x=3 and x=-2.

The correct answer is: C. x = 3, -2

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