What is the solution set of the quadratic inequality -3(x - 2)^2 + 12 0?

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What is the solution set of the quadratic inequality -3(x - 2)^2 + 12 > 0? Enter the answers in each space provided. Use numbers instead of words. x ∈ ( , )

SnapAndSolve AI · Accepted Answer

First, solve the inequality -3(x - 2)^2 + 12 > 0.

Rewrite the inequality: -3(x - 2)^2 > -12
Divide both sides by -3 (remember to reverse the inequality sign): (x - 2)^2 < 4
Take the square root of both sides: -2 < x - 2 < 2
Add 2 to all parts: 0 < x < 4

Therefore, the solution set is:

x ∈ (0, 4)

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What is the solution set of the quadratic inequality -3(x - 2)^2 + 12 > 0?

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