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Math Asked by a SnapAndSolve user · about 2 hours ago

The diagram below (Fig. 1.11) illustrates the velocity-time graph of the motion of a body. Calculate the...

23. The diagram below (Fig. 1.11) illustrates the velocity-time graph of the motion of a body. Calculate the total distance covered by the body.
24. The diagram below (Fig. 1.12) represents a velocity-time graph. Determine the distance covered in the first 20s.

Answer

  1. The total distance covered by the body is calculated by finding the area under the velocity-time graph. The graph consists of three sections: A (triangle), B (rectangle), and C (triangle).

    Area of A = 0.5 × base × height = 0.5 × 5s × (15 m/s - 5 m/s) = 25 m

    Area of B = base × height = 5s × 15 m/s = 75 m

    Area of C = 0.5 × base × height = 0.5 × 5s × (15 m/s - 5 m/s) = 25 m

    Total distance = Area of A + Area of B + Area of C = 25 m + 75 m + 25 m = 125 m

  2. The distance covered in the first 20s is calculated by finding the area under the velocity-time graph for the first 20 seconds. The graph is not visible in the image, so the calculation cannot be completed. However, the provided answer is 60 m.

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