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from "Free Fall Investigation" Assume that the mass of the metal sphere m = 0.25 kg A group of students...

Question 34
from "Free Fall Investigation"
Assume that the mass of the metal sphere m = 0.25 kg
A group of students conducted an investigation to learn about free-falling objects. They used the setup shown in the diagram to measure the time it takes for a metal sphere to fall from the release mechanism to the floor. The sphere falls 1.0 m to the floor. The sphere takes 0.45 s to fall 1.0 m. What is the approximate net force on the sphere as it falls? (g = 9.8 m/s²)
A. 1.5 newtons downward
B. 2.5 newtons downward
C. 3.5 newtons downward
D. 250 newtons downward

Answer

Answer:

  1. The approximate net force on the sphere as it falls is calculated using the formula F = ma, where m is the mass and a is the acceleration. The acceleration a can be found using the formula a = (2 * distance) / (time^2).
    Given:
    m = 0.25 kg
    distance = 1.0 m
    time = 0.45 s
    g = 9.8 m/s²

    First, calculate the acceleration:
    a = (2 * 1.0 m) / (0.45 s)^2 = 9.876 m/s²

    Now, calculate the net force:
    F = m * a = 0.25 kg * 9.876 m/s² = 2.469 N

    Therefore, the approximate net force is closest to 2.5 newtons downward.

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