The solution of |2x - 1| < 7 is an open interval. What is its upper boundary?
The solution of |2x - 1| < 7 is an open interval. What is its upper boundary? Enter a number only.
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info@snapandsolve.comTo solve |2x - 1| < 7, we split it into two inequalities:
1) 2x - 1 < 7
2) 2x - 1 > -7
Solving these:
1) 2x < 8 => x < 4
2) 2x > -6 => x > -3
The solution is -3 < x < 4.
The upper boundary is 4.
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