Web Analytics

Questions › Math

Math Asked by a SnapAndSolve user · about 2 hours ago

There are 20 children in the cast of a class play, and 8 of the children are boys. Of the boys, 4 have a...

15. There are 20 children in the cast of a class play, and 8 of the children are boys. Of the boys, 4 have a speaking part in the play, and of the girls, 8 do not have a speaking part in the play. If a child from the cast of the play is chosen at random, what is the probability that the child has a speaking part?
A. 2/5
B. 1/2
C. 3/5
D. 3/4
16. The variables x and y are directly proportional, and y = 4 when x = 9. What is the value of y when x = 18?
A. 4
B. 8
C. 6
D. 2

Answer

  1. To find the probability that a child has a speaking part, we need to determine the total number of children with speaking parts. There are 8 boys, and 4 of them have speaking parts. There are 20 - 8 = 12 girls, and 12 - 8 = 4 of them have speaking parts. So, the total number of children with speaking parts is 4 (boys) + 4 (girls) = 8. The probability is therefore 8/20 = 2/5. A. 2/5

  2. Since x and y are directly proportional, y = kx for some constant k. Given y = 4 when x = 9, we have 4 = k * 9, so k = 4/9. When x = 18, y = (4/9) * 18 = 8. B. 8

Have a similar question?

Snap a photo of your homework and get a step-by-step answer in seconds. You can ask follow-up questions until it makes sense.

Solve my question free Math help Find a math tutor

More math questions