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Workout: 2521 + 2141 2. In the figure below, shade B - A. 3. In the sequence below, find the sum of the...

1. Workout: 2521 + 2141
2. In the figure below, shade B - A.
3. In the sequence below, find the sum of the next two numbers.
4. Simplify 5/8 + 1/4.
5. Round off 9103.382 to one decimal place.
6. Using a ruler, a pencil and a pair of compasses, bisect the angle below.
7. The cost of 3 kg of sugar is sh. 18,000. Amirah bought 4 1/2 kg of sugar. How much did she pay?
8. Write the number represented by the Roman numeral below in words. DCCLXIV
9. Given that a = 3b and c = 2/3, find the value of b if a = 8c.
10. Find the least number of apples when shared by 9 pupils or 12 pupils leaves a remainder of 5.
11. Find the average of 2k, 7k, 0, k, 5.
12. A meeting which started at 10:40 am took 2 hours and 50 minutes, at what time did it end?
13. A cyclist covered a distance of 30m in 20 seconds. Express his speed in km/h.
14. Change 4,321 Litres of water into ml.
15. Given set P = {a, e, i, o, u}. List all possible subsets that can be formed from set P.
16. Find the area of the trapezium below.

Answer

  1. 2521 + 2141 = 4662

  2. Shade the region that belongs to set B but not to set A.

  3. The sequence is 8, 27, 64. The next two numbers are 125 and 216. Sum = 125 + 216 = 341.

  4. 5/8 + 1/4 = 5/8 + 2/8 = 7/8

  5. 9103.382 rounded to one decimal place is 9103.4

  6. Use a ruler and compass to bisect the given angle.

  7. 3 kg costs 18,000, so 1 kg costs 6,000. 4.5 kg costs 4.5 * 6,000 = 27,000 sh.

  8. DCCLXIV is 764 in words: Seven hundred sixty-four.

  9. a = 3b and c = 2/3, a = 8c. 8c = 8 * (2/3) = 16/3. 3b = 16/3, b = 16/9.

  10. Find the least common multiple of 9 and 12, then add 5. LCM(9, 12) = 36. Least number = 36 + 5 = 41.

  11. Average = (2k + 7k + 0 + k + 5)/5 = (10k + 5)/5 = 2k + 1

  12. 10:40 am + 2 hours 50 minutes = 1:30 pm.

  13. Speed = Distance/Time = 30m/20s = 1.5 m/s. Convert to km/h: 1.5 * 3.6 = 5.4 km/h.

  14. 4,321 Litres = 4,321,000 ml.

  15. Possible subsets: {}, {a}, {e}, {i}, {o}, {u}, {a, e}, {a, i}, {a, o}, {a, u}, {e, i}, {e, o}, {e, u}, {i, o}, {i, u}, {o, u}, {a, e, i}, {a, e, o}, {a, e, u}, {a, i, o}, {a, i, u}, {a, o, u}, {e, i, o}, {e, i, u}, {e, o, u}, {i, o, u}, {a, e, i, o}, {a, e, i, u}, {a, e, o, u}, {a, i, o, u}, {e, i, o, u}, {a, e, i, o, u}

  16. Area of trapezium = 1/2 * (sum of parallel sides) * height = 1/2 * (7m + 3m) * 5m = 25 square meters.

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