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What is the slope of her climb? 4. When would the slope of Abha's climb be negative?

1. What is the slope of her climb?
4. When would the slope of Abha's climb be negative?
5. Does the line 5x - y = 13x pass through the origin? How do you know?
6. Daliyah is given one point on a line at (3, -1) and the slope of the line as -5.
A. What is the y-intercept of the line?
B. Write the equation of the line.
Open Ended: Write one linear and one nonlinear equation.
For Problems 8-9, write the equation in slope-intercept form, identify the sign of the slope, and state whether the line passes through the origin.
8. 2y = 3x + 4
9. -5 = -y - 2x

Answer

  1. The slope of Abha's climb is calculated as the change in elevation divided by the horizontal distance. Therefore, the slope is 40/20 = 2.

  2. The slope of Abha's climb would be negative if she were descending instead of ascending.

  3. The equation 5x - y = 13x is not correctly written. Assuming the intended equation is 5x - y = 13, it does not pass through the origin because substituting (0,0) into the equation does not satisfy it.

    1. Using the point-slope form, y - (-1) = -5(x - 3), the y-intercept can be found by setting x = 0: y = -5(0 - 3) - 1 = 15 - 1 = 14. So, the y-intercept is 14.

    2. The equation of the line is y + 1 = -5(x - 3), which simplifies to y = -5x + 15 - 1, or y = -5x + 14.

  4. Linear equation example: y = 2x + 3. Nonlinear equation example: y = x^2 + 3.

    1. For 2y = 3x + 4, divide by 2 to get y = (3/2)x + 2. The slope is positive (3/2), and it does not pass through the origin because the y-intercept is 2.

    2. For -5 = -y - 2x, rearrange to y = -2x + 5. The slope is negative (-2), and it does not pass through the origin because the y-intercept is 5.

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