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Math Asked by a SnapAndSolve user · 21 minutes ago

Solve 6(2^(x+5)) + 4 = 11 and approximate the result to three decimal places.

Solve 6(2^(x+5)) + 4 = 11 and approximate the result to three decimal places.

Answer

First, isolate the exponential term:

6(2^(x+5)) + 4 = 11
6(2^(x+5)) = 7
2^(x+5) = 7/6

Take the logarithm of both sides:

log(2^(x+5)) = log(7/6)
(x+5) * log(2) = log(7/6)
x+5 = log(7/6) / log(2)
x = log(7/6) / log(2) - 5

Calculate the value:

x ≈ -4.736

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