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An object is dropped from 33 feet below the tip of the pinnacle atop a 357-ft tall building. The height h...

An object is dropped from 33 feet below the tip of the pinnacle atop a 357-ft tall building. The height h of the object after t seconds is given by the equation h = -16t^2 + 324. Find how many seconds pass before the object reaches the ground.
seconds pass before the object reaches the ground (Type an integer or a decimal.)

Answer

To find how many seconds pass before the object reaches the ground, set h = 0 and solve for t in the equation:

0 = -16t^2 + 324

Rearrange the equation:

16t^2 = 324

Divide both sides by 16:

t^2 = 20.25

Take the square root of both sides:

t = 4.5

Therefore, 4.5 seconds pass before the object reaches the ground.

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