Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(2v^3 + 13v^2 + 6v) ÷ (v + 6)

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (2v^3 + 13v^2 + 6v) ÷ (v + 6)

SnapAndSolve AI · Accepted Answer

To divide the polynomial (2v^3 + 13v^2 + 6v) by (v + 6), use polynomial long division: Divide the first term of the dividend by the first term of the divisor: 2v^3 ÷ v = 2v^2. Multiply the entire divisor by this result: 2v^2(v + 6) = 2v^3 + 12v^2. Subtract this from the original polynomial: (2v^3 + 13v^2 + 6v) - (2v^3 + 12v^2) = v^2 + 6v. Repeat the process with the new polynomial: v^2 ÷ v = v. Multiply the entire divisor by this result: v(v + 6) = v^2 + 6v. Subtract this from the new polynomial: (v^2 + 6v) - (v^2 + 6v) = 0. The division is exact, with no remainder. The quotient is 2v^2 + v.

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (2v^3 + 13v^2 + 6v)...

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