Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(-16q^3 - 165q^2 - 50q) ÷ (q + 10)

Question

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-16q^3 - 165q^2 - 50q) ÷ (q + 10)

SnapAndSolve AI · Accepted Answer

To divide the polynomial (-16q^3 - 165q^2 - 50q) by (q + 10), we use polynomial long division:

Divide the first term of the dividend by the first term of the divisor: -16q^3 ÷ q = -16q^2.
Multiply the entire divisor by this result: -16q^2(q + 10) = -16q^3 - 160q^2.
Subtract this from the original polynomial: (-16q^3 - 165q^2 - 50q) - (-16q^3 - 160q^2) = -5q^2 - 50q.
Repeat the process: Divide -5q^2 by q: -5q.
Multiply the entire divisor by this result: -5q(q + 10) = -5q^2 - 50q.
Subtract this from the current polynomial: (-5q^2 - 50q) - (-5q^2 - 50q) = 0.

The quotient is -16q^2 - 5q with a remainder of 0.

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-16q^3 - 165q^2 -...