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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (9u^2 - 66u - 50) ÷...

Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(9u^2 - 66u - 50) ÷ (u - 8)

Answer

To divide the polynomial (9u^2 - 66u - 50) by (u - 8), use polynomial long division:

Divide the first term of the dividend by the first term of the divisor: 9u^2 ÷ u = 9u.
Multiply the entire divisor by this result: 9u(u - 8) = 9u^2 - 72u.
Subtract this from the original polynomial: (9u^2 - 66u - 50) - (9u^2 - 72u) = 6u - 50.
Repeat the process: 6u ÷ u = 6.
Multiply the entire divisor by this result: 6(u - 8) = 6u - 48.
Subtract this from the current remainder: (6u - 50) - (6u - 48) = -2.

The quotient is 9u + 6 with a remainder of -2. Therefore, the result is:

9u + 6 - 2/(u - 8)

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