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Math Asked by a SnapAndSolve user · about 10 hours ago

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-18j^2 + 126j - 20)...

Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(-18j^2 + 126j - 20) ÷ (j - 7)

Answer

To divide the polynomial (-18j^2 + 126j - 20) by (j - 7), we use polynomial long division:

Divide the first term of the dividend (-18j^2) by the first term of the divisor (j), which gives -18j.
Multiply the entire divisor (j - 7) by -18j to get (-18j^2 + 126j).
Subtract this result from the original polynomial: (-18j^2 + 126j - 20) - (-18j^2 + 126j) = -20.
Since -20 is a constant and cannot be divided by (j - 7), it is the remainder.

The quotient is -18j with a remainder of -20, so the result is:

-18j - 20/(j - 7)

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