Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(-9a^3 + 15a^2 + 36a) ÷ (a - 3)

Question

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-9a^3 + 15a^2 + 36a) ÷ (a - 3)

SnapAndSolve AI · Accepted Answer

To divide the polynomial (-9a^3 + 15a^2 + 36a) by (a - 3), use polynomial long division:

Divide the first term of the dividend (-9a^3) by the first term of the divisor (a) to get -9a^2.
Multiply the entire divisor (a - 3) by -9a^2 to get (-9a^3 + 27a^2).
Subtract (-9a^3 + 27a^2) from (-9a^3 + 15a^2 + 36a) to get (-12a^2 + 36a).
Divide the first term of the new dividend (-12a^2) by the first term of the divisor (a) to get -12a.
Multiply the entire divisor (a - 3) by -12a to get (-12a^2 + 36a).
Subtract (-12a^2 + 36a) from (-12a^2 + 36a) to get 0.

The quotient is -9a^2 - 12a with a remainder of 0.

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-9a^3 + 15a^2 +...