Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(-5t^3 - 30t^2 + 80t) ÷ (t + 8)

Question

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-5t^3 - 30t^2 + 80t) ÷ (t + 8)

SnapAndSolve AI · Accepted Answer

To divide the polynomial (-5t^3 - 30t^2 + 80t) by (t + 8), we use polynomial long division:

Divide the first term of the dividend (-5t^3) by the first term of the divisor (t), which gives -5t^2.
Multiply the entire divisor (t + 8) by -5t^2, resulting in (-5t^3 - 40t^2).
Subtract this from the original polynomial: (-5t^3 - 30t^2 + 80t) - (-5t^3 - 40t^2) = 10t^2 + 80t.
Repeat the process: Divide 10t^2 by t, which gives 10t.
Multiply the divisor (t + 8) by 10t, resulting in (10t^2 + 80t).
Subtract this from the current polynomial: (10t^2 + 80t) - (10t^2 + 80t) = 0.

The division is exact with no remainder. The quotient is -5t^2 + 10t.

Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-5t^3 - 30t^2 +...