Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(-3k^3 + 100k - 43) ÷ (k + 6)

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-3k^3 + 100k - 43) ÷ (k + 6)

SnapAndSolve AI · Accepted Answer

To divide the polynomial -3k^3 + 100k - 43 by k + 6, we use polynomial long division: Divide the first term of the dividend (-3k^3) by the first term of the divisor (k), which gives -3k^2. Multiply the entire divisor (k + 6) by -3k^2, resulting in -3k^3 - 18k^2. Subtract this from the original polynomial: (-3k^3 + 100k - 43) - (-3k^3 - 18k^2) = 18k^2 + 100k - 43. Repeat the process: Divide 18k^2 by k, giving 18k. Multiply the divisor by 18k, resulting in 18k^2 + 108k. Subtract: (18k^2 + 100k - 43) - (18k^2 + 108k) = -8k - 43. Divide -8k by k, giving -8. Multiply the divisor by -8, resulting in -8k - 48. Subtract: (-8k - 43) - (-8k - 48) = 5. The quotient is -3k^2 + 18k - 8 with a remainder of 5. Therefore, the result is:-3k^2 + 18k - 8 + 5/(k + 6)

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-3k^3 + 100k - 43)...

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