Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(2s^2 - 89) ÷ (s - 7)

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (2s^2 - 89) ÷ (s - 7)

SnapAndSolve AI · Accepted Answer

To divide the polynomial 2s^2 - 89 by s - 7, we use polynomial long division: Divide the first term of the dividend by the first term of the divisor: 2s^2 ÷ s = 2s. Multiply the entire divisor by this result: 2s(s - 7) = 2s^2 - 14s. Subtract this from the original polynomial: (2s^2 - 89) - (2s^2 - 14s) = 14s - 89. Now divide the first term of the new polynomial by the first term of the divisor: 14s ÷ s = 14. Multiply the entire divisor by this result: 14(s - 7) = 14s - 98. Subtract this from the current polynomial: (14s - 89) - (14s - 98) = 9. The quotient is 2s + 14 with a remainder of 9. Therefore, the result of the division is:2s + 14 + 9/(s - 7)

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (2s^2 - 89) ÷ (s - 7)

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