Divide. If the polynomial does not divide evenly, include the remainder as a fraction.
(-7g^4 - 55g^3 - 46g^2 - 29g + 3) ÷ (g + 7)

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-7g^4 - 55g^3 - 46g^2 - 29g + 3) ÷ (g + 7)

SnapAndSolve AI · Accepted Answer

To divide the polynomial -7g^4 - 55g^3 - 46g^2 - 29g + 3 by g + 7, we use polynomial long division: Divide the first term of the dividend by the first term of the divisor: -7g^4 ÷ g = -7g^3. Multiply the entire divisor by this result: -7g^3(g + 7) = -7g^4 - 49g^3. Subtract this from the original polynomial: (-7g^4 - 55g^3) - (-7g^4 - 49g^3) = -6g^3. Bring down the next term: -6g^3 - 46g^2. Repeat the process: -6g^3 ÷ g = -6g^2. Multiply: -6g^2(g + 7) = -6g^3 - 42g^2. Subtract: (-6g^3 - 46g^2) - (-6g^3 - 42g^2) = -4g^2. Bring down the next term: -4g^2 - 29g. Continue: -4g^2 ÷ g = -4g. Multiply: -4g(g + 7) = -4g^2 - 28g. Subtract: (-4g^2 - 29g) - (-4g^2 - 28g) = -g. Bring down the last term: -g + 3. Divide: -g ÷ g = -1. Multiply: -1(g + 7) = -g - 7. Subtract: (-g + 3) - (-g - 7) = 10. The quotient is -7g^3 - 6g^2 - 4g - 1 with a remainder of 10.Thus, the final answer is: -7g^3 - 6g^2 - 4g - 1 + 10/(g + 7).

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Divide. If the polynomial does not divide evenly, include the remainder as a fraction. (-7g^4 - 55g^3 -...

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