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The table shows the following steps: −c = ax² + bx — Use the subtraction property of equality. −c = a(x² +...
The table shows the following steps:
−c = ax² + bx — Use the subtraction property of equality.
−c = a(x² + (b/a)x) — Factor out a.
(b/(2a))² = b²/(4a²) — Find half of the b value and square it to determine the constant of the perfect square trinomial.
−c + b²/(4a) = a(x² + (b/a)x + b²/(4a²))
Which best explains why b²/(4a²) is not added to the left side of the equation in the last step shown in the table?
A. The term b²/(4a²) is added to the right side of the equation, so it needs to be subtracted from the left side of the equation to balance the sides of the equation.
B. The distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.
C. The term b²/(4a²) needs to be converted so it has a common denominator before adding it to the left side of the equation to balance the equation.
D. The square root of the term needs to be found before adding the term to the left side of the equation to balance the sides of the equation.
−c = ax² + bx — Use the subtraction property of equality.
−c = a(x² + (b/a)x) — Factor out a.
(b/(2a))² = b²/(4a²) — Find half of the b value and square it to determine the constant of the perfect square trinomial.
−c + b²/(4a) = a(x² + (b/a)x + b²/(4a²))
Which best explains why b²/(4a²) is not added to the left side of the equation in the last step shown in the table?
A. The term b²/(4a²) is added to the right side of the equation, so it needs to be subtracted from the left side of the equation to balance the sides of the equation.
B. The distributive property needs to be applied to determine the value to add to the left side of the equation to balance the sides of the equation.
C. The term b²/(4a²) needs to be converted so it has a common denominator before adding it to the left side of the equation to balance the equation.
D. The square root of the term needs to be found before adding the term to the left side of the equation to balance the sides of the equation.