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info@snapandsolve.comTo find the energy of a photon, use the formula: E = \( \frac{hc}{\lambda} \), where h is Planck's constant \(6.626 \times 10^{-34} \text{ J s}\), c is the speed of light \(2.998 \times 10^8 \text{ m/s}\), and \(\lambda\) is the wavelength.
For \(\lambda = 1.18 \times 10^6 \text{ m}\):
\[ E = \frac{6.626 \times 10^{-34} \times 2.998 \times 10^8}{1.18 \times 10^6} \]
\[ E \approx 1.68 \times 10^{-31} \text{ J} \]
For \(\lambda = 4.45 \times 10^7 \text{ m}\):
\[ E = \frac{6.626 \times 10^{-34} \times 2.998 \times 10^8}{4.45 \times 10^7} \]
\[ E \approx 4.47 \times 10^{-27} \text{ J} \]
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