The terminal side of an angle θ in standard position in Quadrant I intersects the unit circle at \( (x,...
a. \( \frac{18}{25} \)
b. \( \frac{25}{24} \)
c. \( \frac{24}{25} \)
d. \( \frac{7}{24} \)
To find \( x \), use the equation of the unit circle: \( x^2 + y^2 = 1 \).
Given \( y = \frac{7}{25} \), substitute into the equation:
\( x^2 + \left(\frac{7}{25}\right)^2 = 1 \)
\( x^2 + \frac{49}{625} = 1 \)
\( x^2 = 1 - \frac{49}{625} \)
\( x^2 = \frac{625}{625} - \frac{49}{625} \)
\( x^2 = \frac{576}{625} \)
\( x = \sqrt{\frac{576}{625}} \)
\( x = \frac{24}{25} \)
The correct answer is c. \( \frac{24}{25} \).
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