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info@snapandsolve.comS in Na2SO3: Sodium (Na) has an oxidation state of +1, and oxygen (O) is typically -2. Let x be the oxidation state of sulfur (S). The equation is 2(+1) + x + 3(-2) = 0. Solving gives x = +4. So, S is +4.
B in B2H6: Hydrogen (H) has an oxidation state of +1. Let x be the oxidation state of boron (B). The equation is 2x + 6(+1) = 0. Solving gives x = -3. So, B is -3.
O in CaO2: Calcium (Ca) has an oxidation state of +2. Let x be the oxidation state of oxygen (O). The equation is +2 + 2x = 0. Solving gives x = -1. So, O is -1.
P in H4P2O7: Hydrogen (H) is +1 and oxygen (O) is -2. Let x be the oxidation state of phosphorus (P). The equation is 4(+1) + 2x + 7(-2) = 0. Solving gives x = +5. So, P is +5.
I in Mg(ClO3)2: Magnesium (Mg) is +2, and chlorine (Cl) in ClO3- is typically +5. Let x be the oxidation state of iodine (I). The equation is +2 + 2(x) = 0. Solving gives x = -1. So, I is -1.
Xe in XeF4: Fluorine (F) is -1. Let x be the oxidation state of xenon (Xe). The equation is x + 4(-1) = 0. Solving gives x = +4. So, Xe is +4.
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