Find the vertex of the following quadratic function f(x) = 2x^2 - 6x + 11
a (1.5, 6.5)
b (3.5, 4)
c (1.5, 6)
d (1, 2.5)

Question

Find the vertex of the following quadratic function f(x) = 2x^2 - 6x + 11 a (1.5, 6.5) b (3.5, 4) c (1.5, 6) d (1, 2.5)

SnapAndSolve AI · Accepted Answer

The vertex of a quadratic function in the form f(x) = ax^2 + bx + c is given by the formula:

Vertex (h, k) = (-b/2a, f(-b/2a))

For the function f(x) = 2x^2 - 6x + 11:

Calculate h:

h = -(-6)/(2*2) = 6/4 = 1.5

Calculate k:

f(1.5) = 2(1.5)^2 - 6(1.5) + 11 = 2(2.25) - 9 + 11 = 4.5 - 9 + 11 = 6.5

Therefore, the vertex is (1.5, 6.5).

Answer: a (1.5, 6.5)

Find the vertex of the following quadratic function f(x) = 2x^2 - 6x + 11 a (1.5, 6.5) b (3.5, 4) c (1.5,...