Solve the equation $ \frac{1}{6} m + \frac{1}{3} m = 28 \frac{1}{3} $ for $ m $. The solution to the...

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Solve the equation $ \frac{1}{6} m + \frac{1}{3} m = 28 \frac{1}{3} $ for $ m $. The solution to the equation is ☐ 3. ☐ 6. ☐ 6$ \frac{2}{3} $. ☐ 9$ \frac{2}{3} $.

SnapAndSolve AI · Accepted Answer

To solve the equation $ \frac{1}{6} m + \frac{1}{3} m = 28 \frac{1}{3} $, first find a common denominator for the fractions on the left side. The common denominator of 6 and 3 is 6. Rewrite $ \frac{1}{3} m $ as $ \frac{2}{6} m $. Add the fractions: $ \frac{1}{6} m + \frac{2}{6} m = \frac{3}{6} m = \frac{1}{2} m $. Set the equation: $ \frac{1}{2} m = 28 \frac{1}{3} $. Convert $ 28 \frac{1}{3} $ to an improper fraction: $ 28 \frac{1}{3} = \frac{85}{3} $. Multiply both sides by 2 to solve for $ m $: $ m = 2 \times \frac{85}{3} = \frac{170}{3} $. Convert $ \frac{170}{3} $ to a mixed number: $ 56 \frac{2}{3} $. The solution to the equation is 6$ \frac{2}{3} $.

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Solve the equation \( \frac{1}{6} m + \frac{1}{3} m = 28 \frac{1}{3} \) for \( m \). The solution to the...

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