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Chemistry Asked by a SnapAndSolve user · about 1 hour ago

Based on the below chemical equation describing making smores, if 30 moles of chocolate were used fully,...

5. Based on the below chemical equation describing making smores, if 30 moles of chocolate were used fully, how many moles of smore would be produced? Show your work using the provided t-chart.
2 graham crackers + 1 marshmallow + 3 chocolate -> 1 smore
30 moles chocolate
6. Based on the below balanced chemical equation, if 10 moles of ethane (C2H6) is fully reacted, how many moles of carbon dioxide would be produced? Show work in t-chart.
2C2H6 + 7O2 -> 4CO2 + 6H2O
10 moles C2H6
7. Based on the below balanced chemical equation if 7.5 moles of CO2 was produced, how many moles of O2 went into the reaction? Build your own t-chart to solve this problem.
2 CO + O2 -> 2 CO2
8. Challenge problem: In the reaction below if 65 grams of KClO3 reacts fully, how many grams of oxygen gas (O2) will be produced?
2 KClO3 -> 2 KCl + 3 O2
Calculate the molar mass of KClO3, below: Calculate the molar mass of O2, below:
65 grams KClO3

Answer

  1. According to the equation, 3 moles of chocolate produce 1 mole of smore. Therefore, 30 moles of chocolate would produce:

    30 moles chocolate x (1 mole smore / 3 moles chocolate) = 10 moles smore

  2. According to the equation, 2 moles of C2H6 produce 4 moles of CO2. Therefore, 10 moles of C2H6 would produce:

    10 moles C2H6 x (4 moles CO2 / 2 moles C2H6) = 20 moles CO2

  3. According to the equation, 2 moles of CO produce 2 moles of CO2. Therefore, 7.5 moles of CO2 would require:

    7.5 moles CO2 x (1 mole O2 / 2 moles CO2) = 3.75 moles O2

  4. First, calculate the molar mass of KClO3 and O2:

    • KClO3: K = 39.1 g/mol, Cl = 35.5 g/mol, O3 = 48 g/mol; Total = 122.6 g/mol
    • O2: O2 = 32 g/mol

    65 grams KClO3 x (1 mole KClO3 / 122.6 grams KClO3) x (3 moles O2 / 2 moles KClO3) x (32 grams O2 / 1 mole O2) = 25.4 grams O2

    25.4 grams O2

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