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In Jacksonville Beach, Florida, the ocean temperature decreased by an average of 2°F each month for 5...

In Jacksonville Beach, Florida, the ocean temperature decreased by an average of 2°F each month for 5 months and then increased by an average of 4°F for 7 months. In St. Petersburg, Florida, the ocean temperature decreased by 4°F for 5 months and then increased by 2°F for 7 months. In which location did the ocean have a greater change in temperature? Explain.
Jacksonville Beach had a total temperature change of □ + 5 * □ + 7 * □, and St. Petersburg had a total temperature change of □ + 5 * □ + 7 * □. So the ocean □ had a greater change in temperature. (Type whole numbers.)

Answer

Jacksonville Beach: The temperature change is calculated as follows:

  1. Decrease: 2°F for 5 months = 2 * 5 = 10°F decrease
  2. Increase: 4°F for 7 months = 4 * 7 = 28°F increase
  3. Total change: 28 - 10 = 18°F increase

St. Petersburg: The temperature change is calculated as follows:

  1. Decrease: 4°F for 5 months = 4 * 5 = 20°F decrease
  2. Increase: 2°F for 7 months = 2 * 7 = 14°F increase
  3. Total change: 14 - 20 = 6°F decrease

Jacksonville Beach had a total temperature change of 0 + 5 * (-2) + 7 * 4 = 18°F, and St. Petersburg had a total temperature change of 0 + 5 * (-4) + 7 * 2 = -6°F. So the ocean in Jacksonville Beach had a greater change in temperature.

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