Line r has an equation of y = (6/7)x + 1. Line s includes the point (7, -7) and is perpendicular to line r....

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Line r has an equation of y = (6/7)x + 1. Line s includes the point (7, -7) and is perpendicular to line r. What is the equation of line s?

SnapAndSolve AI · Accepted Answer

To find the equation of line s, we need to determine its slope. Since line s is perpendicular to line r, its slope will be the negative reciprocal of the slope of line r.

The slope of line r is 6/7.
The negative reciprocal of 6/7 is -7/6.
Using the point-slope form of a line equation, y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is a point on the line:
Substitute m = -7/6 and the point (7, -7):
y + 7 = -7/6(x - 7)
y + 7 = -7/6x + 49/6
y = -7/6x + 49/6 - 42/6
y = -7/6x + 7/6

Therefore, the equation of line s is y = -7/6x + 7/6.

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Line r has an equation of y = (6/7)x + 1. Line s includes the point (7, -7) and is perpendicular to line r....

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