Solve the system of equations.
x + y + z = 0
x - y + 5z = 22
2x + y + z = 2
A. {(2, -5, 3)}
B. {(-5, 2, 3)}
C. {(3, -5, 2)}
D. {(3, 2, -5)}

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Solve the system of equations. x + y + z = 0 x - y + 5z = 22 2x + y + z = 2 A. {(2, -5, 3)} B. {(-5, 2, 3)} C. {(3, -5, 2)} D. {(3, 2, -5)}

SnapAndSolve AI · Accepted Answer

Solution: Equation 1: x + y + z = 0 Equation 2: x - y + 5z = 22 Equation 3: 2x + y + z = 2 Let's solve the system using substitution or elimination: From Equation 1: y = -x - z Substitute y in Equation 3: 2x + (-x - z) + z = 2, simplifying gives x = 2 Substitute x = 2 in Equation 1: 2 + y + z = 0, so y + z = -2 Substitute x = 2 in Equation 2: 2 - y + 5z = 22, so -y + 5z = 20 From y + z = -2, y = -2 - z Substitute y = -2 - z in -y + 5z = 20: -(-2 - z) + 5z = 20, simplifying gives 6z = 18, so z = 3 Substitute z = 3 in y = -2 - z: y = -2 - 3 = -5 Solution: x = 2, y = -5, z = 3 Answer: A. {(2, -5, 3)}

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Solve the system of equations. x + y + z = 0 x - y + 5z = 22 2x + y + z = 2 A. {(2, -5, 3)} B. {(-5, 2, 3)}...

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