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Solve the equation. 6^(x-2)=6^5 a. x=3 b. x=5 c. x=7 d. x=10 2. What is an extraneous solution?

1. Solve the equation. 6^(x-2)=6^5
a. x=3
b. x=5
c. x=7
d. x=10
2. What is an extraneous solution?
a. A possible solution that does not satisfy the original equation
b. A solution with a decimal value
c. A solution that cannot be rounded
d. A solution that is always correct
3. A car's value is modeled by V(t)=24000(0.82)^t. Which equation should be solved to find when the car's value reaches $10000?
a. 10000=0.82(24000)^t
b. 10000=24000(0.82)^t
c. 24000=10000(0.82)^t
d. 24000=10000(0.82)^(24000)

Answer

  1. The equation is 6^(x-2) = 6^5. By equating the exponents, we get x-2 = 5. Solving for x gives x = 7. Answer: c. x=7

  2. An extraneous solution is a possible solution that does not satisfy the original equation. Answer: a. A possible solution that does not satisfy the original equation

  3. The equation to solve for when the car's value reaches $10000 is 10000 = 24000(0.82)^t. Answer: b. 10000=24000(0.82)^t

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