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info@snapandsolve.comTo solve \( \sqrt{x+3} = x - 3 \), square both sides to get \( x + 3 = (x - 3)^2 \). Expanding the right side gives \( x + 3 = x^2 - 6x + 9 \). Rearranging gives \( x^2 - 7x + 6 = 0 \). Factoring gives \( (x - 6)(x - 1) = 0 \), so \( x = 6 \) or \( x = 1 \). Checking both solutions in the original equation, \( x = 6 \) works, but \( x = 1 \) does not. Therefore, the solution is {6}.
To solve \(-2x - 1 > -3x + 8\), add \(3x\) to both sides to get \(x - 1 > 8\). Adding 1 to both sides gives \(x > 9\). Therefore, the solution is A. 9 < x.
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