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An object is dropped from 44 feet below the tip of the pinnacle atop a 1200-ft tall building. The height h...

An object is dropped from 44 feet below the tip of the pinnacle atop a 1200-ft tall building. The height h of the object after t seconds is given by the equation h = -16t^2 + 1156. Find how many seconds pass before the object reaches the ground.
seconds pass before the object reaches the ground. (Type an integer or a decimal.)

Answer

To find how many seconds pass before the object reaches the ground, set h = 0 and solve for t:

  1. 0 = -16t^2 + 1156
  2. 16t^2 = 1156
  3. t^2 = 1156 / 16
  4. t^2 = 72.25
  5. t = √72.25
  6. t = 8.5

8.5 seconds pass before the object reaches the ground.

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