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Vertices of ΔXYZ are X(1, -4), Y(-2, -1) and Z(3, 1). For each translation, give the vertices of ΔXYZ'....

1. Vertices of ΔXYZ are X(1, -4), Y(-2, -1) and Z(3, 1). For each translation, give the vertices of ΔXYZ'. T<sub>(-4,-3)</sub>(ΔXYZ)
2. What translation rule maps A(9, -3) to A'(5, -1)?
3. What translation is shown below?
Give the coordinates of each image:
1. T<sub>(-3,-1)</sub>(ΔABC) for A(5, 0), B(-1, 2), C(6, -3)
2. T<sub>(-1,4)</sub>(ΔDEF) for D(3, 3), E(-2, 3), F(0, 2)

Answer

1. Translated Vertices of ΔXYZ

Vertices of ΔXYZ are:

  • X(1, -4)
  • Y(-2, -1)
  • Z(3, 1)

Translation: T(-4,-3)

  1. X' = (1 - 4, -4 - 3) = (-3, -7)
  2. Y' = (-2 - 4, -1 - 3) = (-6, -4)
  3. Z' = (3 - 4, 1 - 3) = (-1, -2)

Vertices of ΔXYZ' are:

  • X'(-3, -7)
  • Y'(-6, -4)
  • Z'(-1, -2)

2. Translation Rule for A(9, -3) to A'(5, -1)

Let the translation be T(x, y).

To find the translation rule, we start with the coordinates:

  • A(9, -3) translates to A'(5, -1)

The translation vector can be determined as follows:

  • x-coordinate change: 5 - 9 = -4
  • y-coordinate change: -1 - (-3) = 2

Thus, the translation rule is:

T(-4, 2)

3. Translations Given Below

1. Translation of ΔABC

Vertices of ΔABC are:

  • A(5, 0)
  • B(-1, 2)
  • C(6, -3)

Translation: T(-3,-1)

  1. A' = (5 - 3, 0 - 1) = (2, -1)
  2. B' = (-1 - 3, 2 - 1) = (-4, 1)
  3. C' = (6 - 3, -3 - 1) = (3, -4)

Vertices of ΔABC' are:

  • A'(2, -1)
  • B'(-4, 1)
  • C'(3, -4)

2. Translation of ΔDEF

Vertices of ΔDEF are:

  • D(3, 3)
  • E(-2, 3)
  • F(0, 2)

Translation: T(-1, 4)

  1. D' = (3 - 1, 3 + 4) = (2, 7)
  2. E' = (-2 - 1, 3 + 4) = (-3, 7)
  3. F' = (0 - 1, 2 + 4) = (-1, 6)

Vertices of ΔDEF' are:

  • D'(2, 7)
  • E'(-3, 7)
  • F'(-1, 6)

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