What is an equation of the line that passes through the point (-6, 3) and is perpendicular to the line 6x -...
What is an equation of the line that passes through the point (-6, 3) and is perpendicular to the line 6x - 5y = 5?
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info@snapandsolve.comTo find the equation of the line that is perpendicular to 6x - 5y = 5 and passes through the point (-6, 3), we first need to find the slope of the given line. The equation 6x - 5y = 5 can be rewritten in slope-intercept form (y = mx + b) as follows:
The slope (m) of the given line is 6/5. The slope of a line perpendicular to this line is the negative reciprocal, which is -5/6.
Now, use the point-slope form of the equation of a line (y - y₁ = m(x - x₁)) with the point (-6, 3) and the slope -5/6:
Thus, the equation of the line is y = -5/6x - 2.
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