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Write the slope-intercept form for the linear equation 3x + 4y = 16. A) y = \frac{3}{4}x + 4 B) 4 =...

7. Write the slope-intercept form for the linear equation 3x + 4y = 16.
A) y = \frac{3}{4}x + 4
B) 4 = -\frac{3}{4}x + y
C) y = -\frac{3}{4}x + 4
D) 4y = 16 - 3x

Answer

Answer: The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept. To convert 3x + 4y = 16 into this form, solve for y:

  1. Subtract 3x from both sides: 4y = -3x + 16
  2. Divide every term by 4: y = -\frac{3}{4}x + 4

The correct answer is C) y = -\frac{3}{4}x + 4.

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