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A car on a straight road is at rest at position x = 0 from time t = 0 to t = 1 s. At t = 5 s, the car is at...

A car on a straight road is at rest at position x = 0 from time t = 0 to t = 1 s. At t = 5 s, the car is at position x = 40 m, and at time t = 10 s, the car is at position x = 80 m. Is the average velocity of the car between t = 0 and t = 5 s less than the average velocity of the car between t = 5 s and t = 10 s? Why or why not?
(A) Yes, because the car has zero velocity for part of the first time interval.
(B) Yes, because the acceleration of the car is less during the first time interval.
(C) No, because the car travels the same distance over the same amount of time in both intervals.
(D) No, because the car had to go faster in the first time interval since it was at rest for the first second.

Answer

Answer: C

The average velocity is calculated as the total displacement divided by the total time. Between t = 0 and t = 5 s, the car travels 40 m in 5 s, giving an average velocity of 8 m/s. Between t = 5 s and t = 10 s, the car also travels 40 m in 5 s, giving the same average velocity of 8 m/s. Therefore, the average velocities are equal, and option C is correct.

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