A quadratic function has vertex (0, -3) and passes through the point (10, -8). Which equation represents...
f(x) = -\frac{1}{20}(x + 3)^2
f(x) = \frac{1}{20}(x + 3)^2
f(x) = -\frac{1}{20}x^2 - 3
f(x) = \frac{1}{20}x^2 - 3
The vertex form of a quadratic function is f(x) = a(x - h)^2 + k, where (h, k) is the vertex. Here, the vertex is (0, -3), so the equation becomes f(x) = a(x - 0)^2 - 3 or f(x) = ax^2 - 3.
We need to find the value of 'a' using the point (10, -8):
The correct equation is f(x) = -\frac{1}{20}x^2 - 3.
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