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What is the magnitude and direction of the electric field due to particle 1 at location A?

What is the magnitude and direction of the electric field due to particle 1 at location A?
What is the magnitude and direction of the electric force on the test particle?

Answer

  1. The magnitude of the electric field E due to particle 1 at location A is calculated using the formula:

    E = k * |q1| / r^2

    where k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 is the charge of particle 1 (+5.28 x 10^-18 C), and r is the distance (1.35 x 10^-7 m).

    Substituting the values:

    E = (8.99 x 10^9) * (5.28 x 10^-18) / (1.35 x 10^-7)^2

    E ≈ 2.61 x 10^4 N/C

    The direction of the electric field is away from particle 1 since it is a positive charge.

  2. The magnitude of the electric force F on the test particle is calculated using the formula:

    F = q * E

    where q is the charge of the test particle (+4.80 x 10^-19 C) and E is the electric field calculated previously (2.61 x 10^4 N/C).

    Substituting the values:

    F = (4.80 x 10^-19) * (2.61 x 10^4)

    F ≈ 1.25 x 10^-14 N

    The direction of the electric force is the same as the direction of the electric field, away from particle 1.

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