What is the magnitude and direction of the electric field due to particle 1 at location A?
What is the magnitude and direction of the electric force on the test particle?
The magnitude of the electric field E due to particle 1 at location A is calculated using the formula:
E = k * |q1| / r^2
where k is Coulomb's constant (8.99 x 10^9 N m²/C²), q1 is the charge of particle 1 (+5.28 x 10^-18 C), and r is the distance (1.35 x 10^-7 m).
Substituting the values:
E = (8.99 x 10^9) * (5.28 x 10^-18) / (1.35 x 10^-7)^2
E ≈ 2.61 x 10^4 N/C
The direction of the electric field is away from particle 1 since it is a positive charge.
The magnitude of the electric force F on the test particle is calculated using the formula:
F = q * E
where q is the charge of the test particle (+4.80 x 10^-19 C) and E is the electric field calculated previously (2.61 x 10^4 N/C).
Substituting the values:
F = (4.80 x 10^-19) * (2.61 x 10^4)
F ≈ 1.25 x 10^-14 N
The direction of the electric force is the same as the direction of the electric field, away from particle 1.
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