Find the solution to the system of equations. 2x - y + z = 3 x + 2y + z = 4 2x - y - 2z = 3 x = __, y = __,...
2x - y + z = 3
x + 2y + z = 4
2x - y - 2z = 3
x = __, y = __, z = __
To solve the system of equations, we can use the elimination method.
Subtract Equation 3 from Equation 1:
(2x - y + z) - (2x - y - 2z) = 3 - 3
z + 2z = 0
3z = 0
z = 0
Substitute z = 0 into Equation 1:
2x - y + 0 = 3
2x - y = 3
Substitute z = 0 into Equation 2:
x + 2y + 0 = 4
x + 2y = 4
Now solve the two equations:
Multiply Equation 2 by 2:
2x + 4y = 8
Subtract Equation 1 from this result:
(2x + 4y) - (2x - y) = 8 - 3
5y = 5
y = 1
Substitute y = 1 into Equation 1:
2x - 1 = 3
2x = 4
x = 2
Thus, the solution is:
x = 2, y = 1, z = 0
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