The line described by the equation 3x + y = 4 is graphed on a coordinate plane. Which equation describes...

Question

The line described by the equation 3x + y = 4 is graphed on a coordinate plane. Which equation describes the graph of the line passing through the point (-6, -3) and perpendicular to 3x + y = 4?
A. y = -1/3x - 5
B. y = -1/3x + 3
C. y = 1/3x - 1
D. y = 1/3x - 6

SnapAndSolve AI · Accepted Answer

To find the equation of the line perpendicular to 3x + y = 4, we first find the slope of the given line. Rewriting the equation in slope-intercept form (y = mx + b), we get y = -3x + 4. The slope (m) is -3.

The slope of a line perpendicular to another is the negative reciprocal. Therefore, the slope of the perpendicular line is 1/3.

Using the point-slope form of a line equation, y - y1 = m(x - x1), where (x1, y1) is the point (-6, -3) and m is 1/3, we have:

y + 3 = 1/3(x + 6)

y + 3 = 1/3x + 2

y = 1/3x - 1

Therefore, the correct answer is:

C. y = 1/3x - 1

contact us

Contact Info

The line described by the equation 3x + y = 4 is graphed on a coordinate plane. Which equation describes...

Answer

Have a similar question?

More math questions