Evaluate the expression \( \frac{4 + \sqrt{-9}}{2 + \sqrt{-1}} \) and write the result in the form \( a +...
The real number a equals
The real number b equals
To evaluate \( \frac{4 + \sqrt{-9}}{2 + \sqrt{-1}} \), we first simplify the expression:
\( \sqrt{-9} = 3i \) and \( \sqrt{-1} = i \).
So the expression becomes \( \frac{4 + 3i}{2 + i} \).
Multiply the numerator and denominator by the conjugate of the denominator:
\( \frac{(4 + 3i)(2 - i)}{(2 + i)(2 - i)} \).
The denominator simplifies to \( 4 + 1 = 5 \).
The numerator simplifies as follows:
\( (4 + 3i)(2 - i) = 8 - 4i + 6i - 3i^2 = 8 + 2i + 3 = 11 + 2i \).
Thus, the expression becomes \( \frac{11 + 2i}{5} = \frac{11}{5} + \frac{2}{5}i \).
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