Barium chloride reacts with potassium sulfate. Calculate the grams of potassium chloride that will result...

Question

Barium chloride reacts with potassium sulfate. Calculate the grams of potassium chloride that will result with 22.1 g of barium sulfate.

SnapAndSolve AI · Accepted Answer

To solve this stoichiometry problem, we need to use the balanced chemical equation for the reaction:

BaCl₂ + K₂SO₄ → BaSO₄ + 2 KCl

Calculate the molar mass of BaSO₄:
Molar mass of BaSO₄ = 137.33 (Ba) + 32.07 (S) + 4 × 16.00 (O) = 233.39 g/mol
Convert grams of BaSO₄ to moles:
Moles of BaSO₄ = 22.1 g / 233.39 g/mol = 0.0947 mol
Use the mole ratio from the balanced equation to find moles of KCl:
Mole ratio BaSO₄ : KCl = 1:2
Moles of KCl = 0.0947 mol × 2 = 0.1894 mol
Calculate the molar mass of KCl:
Molar mass of KCl = 39.10 (K) + 35.45 (Cl) = 74.55 g/mol
Convert moles of KCl to grams:
Grams of KCl = 0.1894 mol × 74.55 g/mol = 14.12 g

Therefore, 14.12 grams of potassium chloride will result.

Answer