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info@snapandsolve.comTo graph the equation y = -3x^2 + 6x - 1, first find the vertex using the formula for the vertex of a parabola, x = -b/(2a). Here, a = -3 and b = 6, so x = -6/(2*(-3)) = 1. Substitute x = 1 into the equation to find y: y = -3(1)^2 + 6(1) - 1 = 2. The vertex is (1, 2). The axis of symmetry is x = 1. Plot points around the vertex to complete the graph.
For the equation y = 3(x - 4)^2 + 21, the vertex form of a parabola is y = a(x - h)^2 + k. Here, h = 4 and k = 21, so the vertex is (4, 21). The parabola opens upwards because the coefficient of (x - 4)^2 is positive. The axis of symmetry is x = 4.
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