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Math Asked by a SnapAndSolve user · about 2 hours ago

At noon, a tank contained 8 in. of water. After several hours, it contained 4 in. of water. What is the...

At noon, a tank contained 8 in. of water. After several hours, it contained 4 in. of water. What is the percent decrease of water in the tank?
The percent decrease of water in the tank is []%.

Answer

To find the percent decrease, use the formula:

Percent Decrease = ((Original Amount - New Amount) / Original Amount) * 100%

Original Amount = 8 in.

New Amount = 4 in.

Percent Decrease = ((8 - 4) / 8) * 100% = (4 / 8) * 100% = 0.5 * 100% = 50%

The percent decrease of water in the tank is 50%.

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